AP Free Response Question
2007 Form B - B3
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In the circuit above, a 12.0 V battery is connected to two resistors, one of resistance 1000 ohms and the other of resistance 500 ohms. A capacitor with a capacitance of 30 x 10
-6
F is connected in parallel with the 500-ohm resistor. The circuit has been connected for a long time, and all currents have reached their steady states.
(a) Calculate the current in the 500-ohm resistor.
(b) Circuit Elements
i. Draw an ammeter in the circuit above in a location such that it could measure the current in the 500-ohm resistor. Use the symbol
to indicate the ammeter.
ii. Draw a voltmeter in the circuit above in a location such that it could measure the voltage across the 1000-ohm resistor. Use the symbol
to indicate the voltmeter.
(c) Calculate the charge stored on the capacitor.
(d) Calculate the power dissipated in the 1000-ohm resistor.
(e) The capacitor is now discharged, and the 500-ohm resistor is removed and replaced by a resistor of greater resistance. The circuit is reconnected, and currents are again allowed to come to their steady-state values. Is the charge now stored on the capacitor larger, smaller, or the same as it was in part (c)? Justify your answer.
Topic Formulas
Description
Published Formula
capacitance
capacitors in parallel
capacitors in series
Coulomb's Law
electric current
electric field
electric potential energy
energy stored in a capacitor
Joule's Law
Ohm's Law
parallel-plate capacitor
potential and electric field strength
potential due to a collection of point charges
resistance in parallel
resistance in series
resistivity
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