Directions: On this worksheet you will be investigating the relationships between momentum and energy.

Question 1
If F_{max} = 17 N and F_{min} = -12 N then calculate the impulse delivered to a 3-kg mass during the 5 seconds graphed above.

-2 N sec35 N sec-13 N sec47 N sec-1 N sec

Question 2
If the object's initial velocity in Question 1 was 6.5 m/sec, what will be its final velocity at the end of these 5 seconds?

-6.8 m/sec2.2 m/sec1.8 m/sec6.2 m/sec18.5 m/sec

Question 3
What was the magnitude of the average force acting on the 3-kg mass in Question 1 during the 5 seconds displayed on the graph?

-0.2 N2.5 N-5 N7 N-2.6 N

Question 4
A 6.5-gram bullet moving at 290 m/sec travels through a block of wood and emerges out the other side moving at 200 m/sec. If it takes 26.9 µsecs (1 µsec = 1 x 10^{-6} seconds) for the bullet to bore through the wood, what average force did the wood exert on the bullet?

1.18 x 10^{6} N7.01 x 10^{4} N4.83 x 10^{4} N-2.17 x 10^{4} N

Question 5
During target practice, a man shoots a 6.5-gram bullet with a horizontal velocity of 200 m/sec at a 1.5-kg wooden block balanced on the top of a 1.2-meter tall fence post. If the bullet embeds in the block, how fast will the block-bullet be knocked off the post?

0.049 m/sec0.86 m/sec133.33 m/sec199.14 m/sec

Question 6
After being knocked off, how far from the base of the fence post will the block in Question 5 hit the ground?

0.7 m0.43 m0.21 m0.99 m0.3 m

Question 7
A second 6.5-gram bullet is fired at another 1.5-kg block which is initially at rest on a table. The bullet embeds in the block resulting in the block sliding 153 centimeters before coming to a stop. The coefficient of friction between the block and the table's surface is µ = 0.362.How much work will the friction between the table and block do on the block while bringing it to a stop?

3.5 J5.3 J8.2 J55.4 J22.6 J

Question 8
How fast was the original bullet in Question 7 travelling before it struck the block?

Question 9
As shown in the diagrams provided below, a ball of mass 1 kg is originally moving along the x-axis with a velocity of 12 m/sec towards the origin. As it approaches the origin, it delivers a glancing blow to a stationary 2-kg mass. After the collision, the 1-kg ball continues traveling towards the left, into the second quadrant, at a reduced speed of 5 m/sec at an angle of 37º above the negative x-axis.

What is the final momentum of the 2-kg mass after the collision?

3 kg m/sec17 kg m/sec6 kg m/sec8 kg m/sec8.5 kg m/sec

Question 10
Within the system, what fraction of the 1-kg ball's original KE remains after the collision?