Directions: On this worksheet you will be investigating the relationships between momentum and energy.

Question 1 If F_{max} = 16 N and F_{min} = -12 N then calculate the impulse delivered to a 5-kg mass during the 5 seconds graphed above.

-4 N sec-2 N sec34 N sec-14 N sec46 N sec

Question 2 If the object's initial velocity in Question 1 was 6.2 m/sec, what will be its final velocity at the end of these 5 seconds?

-6.6 m/sec5.8 m/sec0.8 m/sec29 m/sec3.4 m/sec

Question 3 What was the magnitude of the average force acting on the 5-kg mass in Question 1 during the 5 seconds displayed on the graph?

2 N-10 N-2.8 N6.8 N-0.4 N

Question 4 A 6.2-gram bullet moving at 300 m/sec travels through a block of wood and emerges out the other side moving at 210 m/sec. If it takes 29.8 µsecs (1 µsec = 1 x 10^{-6} seconds) for the bullet to bore through the wood, what average force did the wood exert on the bullet?

-1.87 x 10^{4} N1.06 x 10^{6} N4.37 x 10^{4} N6.24 x 10^{4} N

Question 5 During target practice, a man shoots a 6.2-gram bullet with a horizontal velocity of 210 m/sec at a 2.5-kg wooden block balanced on the top of a 1.2-meter tall fence post. If the bullet embeds in the block, how fast will the block-bullet be knocked off the post?

209.48 m/sec84 m/sec0.074 m/sec0.52 m/sec

Question 6 After being knocked off, how far from the base of the fence post will the block in Question 5 hit the ground?

1.04 m0.26 m0.73 m0.13 m0.18 m

Question 7 A second 6.2-gram bullet is fired at another 2.5-kg block which is initially at rest on a table. The bullet embeds in the block resulting in the block sliding 156 centimeters before coming to a stop. The coefficient of friction between the block and the table's surface is µ = 0.393.How much work will the friction between the table and block do on the block while bringing it to a stop?

61.3 J38.3 J9.7 J15.1 J6.2 J

Question 8 How fast was the original bullet in Question 7 travelling before it struck the block?

Question 9 As shown in the diagrams provided below, a ball of mass 1 kg is originally moving along the x-axis with a velocity of 12 m/sec towards the origin. As it approaches the origin, it delivers a glancing blow to a stationary 2-kg mass. After the collision, the 1-kg ball continues traveling towards the left, into the second quadrant, at a reduced speed of 5 m/sec at an angle of 37º above the negative x-axis.

What is the final momentum of the 2-kg mass after the collision?

8 kg m/sec8.5 kg m/sec3 kg m/sec6 kg m/sec17 kg m/sec

Question 10 Within the system, what fraction of the 1-kg ball's original KE remains after the collision?