Emission Spectral Lines
While Rutherford was doing his pioneering work leading to the discovery of the atomic nucleus, chemists were completing spectra analysis of different elements. They found that each element, when excited in its gaseous state, produced a unique spectral fingerprint of brightly colored lines which could be seen when viewed through closely separated slits. The element most studied was hydrogen which had three distinctively observable lines in the visible spectrum - red, blue/cyan, and violet. It was noted that the lines were always there and that the spacing between these lines became smaller and smaller.
The first person to propose a mathematical relationship for these lines was J. J. Balmer and we now call hydrogen's visible spectrum the Balmer series. Another pattern in hydrogen's spectral lines was noted by J. Rydberg and W. Ritz. When you added together the frequencies of any two lines, you produced the frequency of a third line. There had to be an atomic model that would predict these patterns. That model was conceived by Neils Bohr (1913). What problems did Rutherford's nuclear model encounter? [1] According to classical physicists, an orbiting electron should radiate energy at a frequency that would match its orbital frequency. Eventually, it would radiate its energy completely away, moving closer and closer to the nucleus with each rotation. Emitting a continuous spectrum of electromagnetic radiation as it spiraled to its demise. This would result in the collapse of matter, and chemistry, as we know it. [2] Atoms in a gaseous state produced unique, discrete line spectra, not continuous spectra. What approach did Bohr use in constructing his model of the hydrogen atom in 1913?
ENERGY. Bohr combined Einstein’s photons that were used to explain the photoelectric effect (1905) and Balmer’s empirical formula (1885) which successfully calculated hydrogen’s visible spectral lines to produce a revolutionary quantum theory. Bohr's hypotheses in developing his theory of the hydrogen atom were [1] The hydrogen atom can exist, without radiating any energy, in several stable, stationary, states.
[2] Radiation is only absorbed or released when the atom changes from one of its stationary states to another. The energy of the emitted or absorbed photon, a packet of radiant energy, is equal to the difference in the energy between these two states. This energy is emitted only by electrons during de-excitation and is quantized (While investigating blackbody radiation, Max Planck had discovered that electromagnetic energy was quantized according to the formula
E = hf where
h = 6.63 x 10-34 J sec
and f represents the electromagnetic wave's frequency calculated according to the formula
f = c/λ.
He was awarded the 1918 Nobel Prize in Physics for his work on energy quanta.).
hf = Ef - Eo [3] The quantized electron energy states correspond to electron orbitals of specific radii. This is equivalent to stating that the electron’s angular momentum is quantized.
This assumption that angular momentum is quantized was later proved to be correct based on the wavelength of the orbiting electron’s deBroglie's standing wave. It was found that an orbital radius would be stable if an integer multiple of the electron's deBroglie wavelength, ldeB = h / (mv), equaled the orbital’s circumference.
Upon cross-multiplying and rearranging, this formula matches the required relationship for the assumption of the electron’s quantized angular momentum. As stated earlier, when Planck's quantized energy is applied to Bohr's model, the energy of an emitted photon equals the difference between the energies for each accepted electron orbital, where electrons in higher orbitals have greater energies than those in lower orbitals. This explains why atomic spectra of excited gases produce discreet lines - the electrons make transitions between distinct, well-defined energy levels and lose distinct, well-defined amounts of energy during their "jumps." If you examine the diagram shown below, the highest energy photon will be blue since it is released when the electron transitions between the 4th excited state and the 1st excited state. Red is the lowest energy photon since it represents a transition only between the 2nd excited state and the 1st excited state. These lines are in hydrogen's visible, or Balmer spectrum.
When electron transitions end on the ground state orbital, they produce spectral lines in the Lyman Series. This series is found in the ultraviolet portion of the electromagnetic spectrum. These photons have higher energies than any of the visible photons since ultraviolet radiation has a higher frequency. These photons are also produced when the electrons fall to a lower energy level thus releasing more energetic radiation. When electron transitions end on the second excited state's orbital, they produce spectral lines in the Paschen Series. This series is found in the infrared portion of the electromagnetic spectrum. These photons have lower energies than any of the visible photons since infrared radiation has a lower frequency. These photons are also produced when the electrons fall to a higher energy level thus releasing less energetic radiation. See the energy level diagram shown below.
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